### FUN TIME FORMULA.

Note: this formula may improve, but it works fine.

In short:

A = BT²

B = A/T²

T² = A/B

Where:

A = small magnitude time length

B = large magnitude time length

T² = small time magnitude square

Fully or to the absolute maximum:

T^2 = A/B = 10^2n

T^-2 = B/A = 10^-2n

A = BT^2 = B/T^-2 = tT^1 = t/T^-1 = X × 10^m+n

B = A/T^2 = AT^-2 = t/T^1 = tT^-1 = X × 10^m-n

t = A/T^1 = AT^-1 = BT^1 = B/T^-1 = X × 10^m

T^1 = √(A/B) = A/t = t/B = 10^n

T^-1 = √(B/A) = t/A = B/t = 10^-n

Where:

T^2 = small time magnitude square

T^-2 = large time magnitude square

T^1 = small time magnitude

T^-1 = large time magnitude

A = small magnitude time length

B = large magnitude time length

t = unit time length

m determines length of time

n determines magnitude of time

Note: scientific notation works best as in X × 10^n.

Note: T^2 is just about the exponents.

### Understood k.

The unit of time is always the number plus the decimal. We will take minutes (m) for an example:

m = 65/4 = 16.25

k is always the whole number part of the unit of time in question, (as opposed to the whole number plus the decimal or just the decimal) and although unorthodox, k is an ‘__understood k__’ in that it is the k of the unit of time being subtracted k or the k of the decimal being added k. Taking the above example using minutes (m):

k = 16

The division is always the decimal part of the unit of time for example again using the minutes (m) example above:

s/60 = 1/4 or 0.25

Therefore,

m = k + s/60 = 16 + 0.25 = 16.25 = 65/4

A typical example:

s/60 = 1/4

s/60 is the decimal of minutes.

k = m – s/60 = 16

This means that the whole minutes (k) equals minutes (m) minus the decimal of minutes (s/60). Note k is usually chosen by you at will or at random.

m = k + s/60 = 65/4

This mean that minutes (m) equals whole minutes (k) plus the decimal of minutes (s/60).

Another example with days (d) and hours (h), let’s say:

d = 82319/3456

Hence,

h/24 = d – k = 2831/3456

This means that the decimal of days (h/24) equals days (d) minus whole days (k). Note how d – k is another way to say h/24.

h = (d – k) × 24 = 2831/144

This means that hours (h) equals days (d) minus whole days (k) multiplied by 24. As noted above d – k is another way to say h/24, therefore (d – k) times 24 equals h. Note how the unit of time (h) is encoded in the decimal (h/24) of the previous unit of time (d).

k = h – m/60 = 19

This means that whole hours (k) equals hours (h) minus the decimal of hours (m/60).

O__ k__?